1. The problem statement, all variables and given/known data A 34.6 -cm-diameter coil consists of 25 turns of circular copper wire 2.25 mm in diameter. A uniform magnetic field, perpendicular to the plane of the coil, changes at a rate of 3.55 × 10-3T/s. Determine a. the current I in the loop, b. and the rate dU/dt at which thermal energy is produced. 2. Relevant equations magnetic flux = B*A cos Theta I = magnetic flux / R R = p (L/A) where p is the resistivity of copper 3. The attempt at a solution Here is what I attempted: First, I found the magnetic flux by using the formula: B*A cos Theta multiplying the area by 25 because it's in a coil and using .173 meters for the radius of the coil (3.55*10^-3)(25*.173) = 1.535375*10^-2 then to find I (current) : I = magnetic flux / resistance I calculated resistance by : since it's a coil, I multiplied the L by 25 and the A by 25 R = p (L/A) = 1.68*10^-8 (25*pi*.173 / 25*pi*1.125*10^-2)^2 = 0.001148 plugging in that into the I equation, I = 1.535375e-2 / 0.001148 = 13.374 A This isn't the right answer and I messed something up. I would appreciate if someone could help me with catching my mistake! I appreciate it! Thanks in advance!