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Capacitor Discharge: Charge starts to flow from one plate to the other through the resistor, as it does, the pd across the capacitor drops due to V = Q/C. By kirchoff's 2nd law, going round the circuit the pd across the resistor is equal and opposite to the pd across the capacitor, so the pd across the resistor drops. By I=V/R, the current drops, this means the rate at which charge is transferred between the two plates of the capacitor decreases...resulting in an exponential decay of charge on capacitor.

Is that all correct?

And so if someone can do a similar (qualitative) explanation of the inductor discharge that would be brill!

Cheers