1. The problem statement, all variables and given/known data For the circuit shown in the figure, the inductors have no appreciable resistance and the switch has been open for a very long time. (Image of circuit) (a) The instant after closing the switch, what is the current through the 60.0-Ω resistor? (b) The instant after closing the switch, what is the potential difference across the 15.0-mH inductor? (c) After the switch has been closed and left closed for a very long time, what is the potential drop across the 60.0-Ω resistor? 2. Relevant equations V=IR I=V/R 3. The attempt at a solution Part A- i assume since we are finding the current through the 60 ohm resister the 10 and 60 ohm resistors will be in series so for the current i just use I=V/R? I ignore both inductors and the 30 ohm resistor right? if so why? I also believe the circuit will act like an open circuit but im at a loss for that. Part B- Apparently the potential difference between the 15 mH inductor is equivalent to the potential difference between the 60 ohm resistor but why is that so? Part C- I realize after some time has passed when the switch is closed the current will not fluctuate as much so there would be no change in current and the inductor behaved like a short circuit where no voltage is induced so the voltage would be 0? still not sure on this.