A bullet is fired directly into a wood block (along the x-axis), which rests on a rough table. The bullet embeds itself in the block. (This is an inelastic collision: the block deforms and the block and bullet heat up as a result of the collision). a) If the bullet has a mass 0.049kg and is initially moving with a speed of 139m[PLAIN]https://s3.lite.msu.edu/adm/jsMath/fonts/cmmi10/alpha/144/char3D.pngs, [Broken] while the block has a mass 0.54kg and is initially at rest, determine the velocity of the block and bullet just after the collision. v[PLAIN]https://s3.lite.msu.edu/adm/jsMath/fonts/cmmi10/alpha/144/char7E.png=[PLAIN]https://s3.lite.msu.edu/adm/jsMath/fonts/cmex10/alpha/144/char1C.png [Broken] 11.5637 m/s , 0 m/s , 0 m/s https://s3.lite.msu.edu/adm/jsMath/fonts/cmex10/alpha/144/char1D.png You are correct. Your receipt no. is 147-6323 b) To determine the velocity of the bullet and block, what did you include in your system? True: The bullet True: The block False: The table You are correct. Your receipt no. is 147-1738 c) Which of the following is true about your assumptions? (Be careful -- some are incorrect because the physics is incorrect!) Select all that are True. 1)I neglected the gravitational force because the collision was short. 2)I neglected the gravitational force because it point in the negative y-direction and therefore doesn't affect the momentum in the x-direction. 3)I neglected the frictional force due to the table because the collision was short. 4)I neglected the upward force of the table force because it points in the y-direction and therefore doesn't affect the momentum in the x-direction. 5)I neglected the upward force of the table force because the collision was short. Incorrect. Tries 2/3 I am confused with last question. To neglect a force since the collision was only .037s seems very iffy to me. Previous attempts were I said all were true, and #2, #4 were true. Both were wrong. My 3rd attempt is telling me #1 #3 #5 are true, what do you think?