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## Homework Statement

A 2kg. lump of clay traveling at a speed of 20m/s collides with and sticks to a 5kg. lump of clay initially at rest and hanging from a string. Find the final speed of the new lump of clay. How high will the clay swing after the collision?

(initial)

m1=2kg.

v1=20m/s

(final)

m2=2kg.+5kg.=7kg.

v2=?

## Homework Equations

KEi=PEf

KEi=1/2(m1)(v1)^2

PEf=(m2)(g)(h)

v=(2gh)^1/2

P=mv - i'm pretty sure you don't need this one

## The Attempt at a Solution

KEi=PEf

(1/2)(2kg.)(20m/s)^2=(7kg.)(9.81m/s^2)(h)

solve for h=?

h=5.825m

solve for v2=?

v2=(2gh)^1/2

v2=10.69m/s

According to the answer given by my teacher h=1.66m if this is correct please show me how.