- #1
lemonlimesoap
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Homework Statement
A 2kg. lump of clay traveling at a speed of 20m/s collides with and sticks to a 5kg. lump of clay initially at rest and hanging from a string. Find the final speed of the new lump of clay. How high will the clay swing after the collision?
(initial)
m1=2kg.
v1=20m/s
(final)
m2=2kg.+5kg.=7kg.
v2=?
Homework Equations
KEi=PEf
KEi=1/2(m1)(v1)^2
PEf=(m2)(g)(h)
v=(2gh)^1/2
P=mv - I'm pretty sure you don't need this one
The Attempt at a Solution
KEi=PEf
(1/2)(2kg.)(20m/s)^2=(7kg.)(9.81m/s^2)(h)
solve for h=?
h=5.825m
solve for v2=?
v2=(2gh)^1/2
v2=10.69m/s
According to the answer given by my teacher h=1.66m if this is correct please show me how.