A car of mass 950kg travelling at 60km/h in an easterly direction collided perfectly inelastically with another care of mass 1250kg travelling at 55.0km/h in a northerly direction. The design of the smaller care incorporated safety features which ensured that any occupants came to rest relative to the care in a tie of 250m/s. Both vehicles had one occupant of 75.0kg
calculate the velocity of the wreckage immediately after the collision.
Use conservation of momentum to determine the change in momentum of both vehicles
m1v1 + m2v2 = m'1v'1 + m'2 v'2
I am not sure if the kinetic energy equation fits here too?
.5 m1 v1 E2 + .5 m2 v2 E2 = .5 m1 v'1E2 + .5 m2v'2E2
r= square root (xE2 +yE2)
The Attempt at a Solution
I converted all the km/h to m/s
I calculated the momentum of each vehicle p=mv (I also included the weight of the driver for each). Using the answers I found the resultant.
I then rearranged the equation to find v and got the right answer in it.
I am now really struggling with the conservation of momentum - these always get me out. I can't seem to use the right equation and am just blank.
Can someone let me know = thank you. :)