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Inelastic collisions

  1. Feb 19, 2006 #1
    i need a help on this problem

    a 20g rifle bullet traveling 250m/s buries itself in a 3.8kg pendulum hanging on a 2.3m-long string. how far does th ependulum swing horizontally?

    Physics 3rd edition Douglas C. Giancoli
     
  2. jcsd
  3. Feb 19, 2006 #2
    also this formuls might be handy

    V1=(m+M)/mv'=(m+M)/√2gh

    g=gravity
     
  4. Feb 19, 2006 #3
    The conservation of momentum

    [tex](M+m)v=mv_0[/tex]

    The conservation of energy

    [tex]\frac{1}{2}(M+m)v^2=(M+m)gl(1-\cos\theta)[/tex]

    The horizontal displacement

    [tex]\Delta x=l\sin\theta[/tex]

    Solving the equation will give you the answer
     
  5. Feb 19, 2006 #4
    thanks i got it
     
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