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Inelastic/elastic collision?

  1. Aug 7, 2009 #1
    The problem statement, all variables and given/known data

    A bullet with a mass of 6.00 g is fired through a 1.25 kg block of wood on a frictionless surface. The initial speed of the bullet is 896 m/s, and the speed of the bullet after it exits the block is 435 m/s. At what speed does the block move after the bullet passes through it?


    The attempt at a solution

    Should I treat this as an inelastic collision even though the two items separate at the end?

    If so, using the (m1)(v1)i + (m2)(v2)i = (m1)(v1)f + (m2)(v2)f formula, I got v2f (final vel. of block) = 2.21 m/s

    Do you agree?
     
  2. jcsd
  3. Aug 7, 2009 #2

    Doc Al

    User Avatar

    Staff: Mentor

    Looks good.

    The collision is inelastic, because KE is not conserved. (Calculate it and see for yourself.) It's not a completely inelastic collision, because they do separate. In any case, all you need to solve it is momentum conservation.
     
  4. Aug 8, 2009 #3
    Most collisions result in the two bodies separating in the end; the case whereby the two bodies coalesce together is a special case of inelastic collisions - a perfectly inelastic collision.
     
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