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**Homework Statement**

A bullet with a mass of 6.00 g is fired through a 1.25 kg block of wood on a frictionless surface. The initial speed of the bullet is 896 m/s, and the speed of the bullet after it exits the block is 435 m/s. At what speed does the block move after the bullet passes through it?

**The attempt at a solution**

Should I treat this as an inelastic collision even though the two items separate at the end?

If so, using the (m1)(v1)i + (m2)(v2)i = (m1)(v1)f + (m2)(v2)f formula, I got v2f (final vel. of block) = 2.21 m/s

Do you agree?