- #1
Rectifier
Gold Member
- 313
- 4
Homework Statement
$$x+\frac{16}{\sqrt{x}} \geq 12$$
How do I show that only x>0 satisfies the inequality above.
Homework Equations
The Attempt at a Solution
I have not made a lot of progress here. I tried the following:
$$x+\frac{16}{\sqrt{x}} - 12 \geq 0$$
I tried to multiply with $$ \sqrt{x} $$ but i am not sure wether that is allowed or not.
I am stuck here :,(