# Inequality with mvt

1. Dec 5, 2008

1. The problem statement, all variables and given/known data

-x<sin(x)<x

2. Relevant equations

show the inequality using the mean value theorem.

3. The attempt at a solution
i try to find c but i keep getting tan(x) as the solution.

2. Dec 5, 2008

### gabbagabbahey

If you show me what you've tried, I can help you better.

3. Dec 5, 2008

f(x)=sin(x) a=-x b=x

f(x)-f(-x)= f'(c) (x+x)
sin(x) = sin(x)=cos(c) (2x)
2sin(x)=2cos(xc)
tan(x)=c

i don't know if that's right, but i don't get the result.

4. Dec 5, 2008

### gabbagabbahey

First, $2x \cos (c) \neq 2 \cos(cx)$ and second $$\frac{\cos(cx)}{\cos (x)}\neq c$$!

Try again, but this time use a=0 and b=x.

What do you know about the maximum and minimum values of cosine of any number?

5. Dec 6, 2008

ok, now i got:

f(x)=sin(x) a=0 b=x

f(x)-f(0)= f'(c) (x-0)
sin(x) =cos(c) (x)
sin(x)/x=cos(c)

im stucked there...
i don't know what you mean with the the maximum and minimum values of cosine of any number.

6. Dec 6, 2008

### gabbagabbahey

Well, cosine is a periodic function that is never greater than 1 or less than negative 1....ring a bell?

That means that $-1\leq \cos (c) \leq 1$ and so....