(adsbygoogle = window.adsbygoogle || []).push({}); 1. The problem statement, all variables and given/known data

[tex]x^3 + 3x^2 - 16x - 48 <= 0[/tex]

factored it down to get this.

[tex](x+3)(x^2 -16) <= 0[/tex]

[tex]x + 3 <= 0[/tex]

[tex]x <= -3[/tex]

[tex]x^2 - 16 <= 0[/tex]

[tex]x <= 4[/tex]

[tex]x <= -4[/tex]

But, that is not right, looking at a graph x needs to be greater than or equal to -3, not less than or equal to. But the other one is right. How come?

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# Homework Help: Inequaltiy problem

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