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Inertia and center of mass

  1. Oct 26, 2004 #1
    A thin 6.0 kg wheel of radius 30 cm is weighted to one side by a 2.0 kg weight, small in size, placed 24 cm from the center of the wheel.
    Calculate the position of the center of mass of the weighted wheel.

    Here's what I have so far.
    I set the origin as the center of the wheel.

    Center of Mass = (6kg*0m)+(2kg*.24m)/8kg = 0.06m away from the center.

    Is that correct?
  2. jcsd
  3. Oct 26, 2004 #2


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    Looks good to me.
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