# Infimum homework problem

## Homework Statement

Find inf{|x-pi|:x$$\in$$Q}

## The Attempt at a Solution

I was thinking that the greatest lower bound must be 0, but that seemed a bit simple. Is there any justification I have to give for this?

Any help would be much appreciated. Cheers. :)

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HallsofIvy
Yes, there exist rational number arbitrarily close to any real number and, in particular, arbitrarily close to $\pi$. The infimum of $|x- \pi|$ for x rational is 0.