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Arrangment as is follows a's are there as place holders to keep the diagram intact while posting, all capacitors have = capacitance C

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The question just asks for the equvilant capacitance.

The professor hinted at the solution by writing 1/ceq = 1/c + 1/ceq where ceq is the equivelent capacitance and the answeris given as (c/2)((5)^(1/2)-1)

___||______||____||____||......

aaaaaa|aaaaaaa|aaaaaa|

aaaaaa=aaaaaaa=aaaaa= .........

aaaaaa|aaaaaaa|aaaaaa|

____________________________

The question just asks for the equvilant capacitance.

The professor hinted at the solution by writing 1/ceq = 1/c + 1/ceq where ceq is the equivelent capacitance and the answeris given as (c/2)((5)^(1/2)-1)

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