1. Not finding help here? Sign up for a free 30min tutor trial with Chegg Tutors
    Dismiss Notice
Dismiss Notice
Join Physics Forums Today!
The friendliest, high quality science and math community on the planet! Everyone who loves science is here!

Infinite Line of Charge

  1. Aug 29, 2009 #1
    An infinite line of negative charge begins at the origin and continues forever in the +y-direction. It has a uniform charge distribution of λ = -2.3 μC/m. Calculate the x and y-component of the electric field at the point (0,-3 m).

    -------

    So immediately realized that Ex = 0 since te charge also lies on the y axis. I cannot seem to evaluate what Ey would be.

    L=Lambda

    Here's what I'm doing: E = 2kL / r
    E = 2(9*10^9)(-2.3*10^-6) / (-3)
    E = 13800 N/C

    What am I doing wrong? Can somebody please help me? I've been working on this problem for a very long time. Thanks in advance.
     
  2. jcsd
  3. Aug 29, 2009 #2

    Doc Al

    User Avatar

    Staff: Mentor

    That formula describes the field surrounding an infinite line of charge at some distance (r) from the line. Not useful for this problem since you are finding the field along the line of the charge and you are dealing with the end of the line of charge. Instead, set up an expression for the field contributed by an element of charge and integrate.
     
  4. Aug 29, 2009 #3
    I don't understand how to set up this integral. Will the limits be from 0 to infinity?

    inf.
    k | (-2.3*10^-6)y / (3+y)^2
    0


    | = integrand

    Does this look right? I seriously do not understand how to set up this equation. Help please!
     
  5. Aug 29, 2009 #4

    Doc Al

    User Avatar

    Staff: Mentor

    That's pretty close. Here's how I would write it:

    (0 to ∞) kλ/(y+3)^2 dy

    Forget the sign of the charge, just worry about the magnitude. You'll assign the proper direction and sign to the field at the end.
     
Know someone interested in this topic? Share this thread via Reddit, Google+, Twitter, or Facebook




Similar Discussions: Infinite Line of Charge
Loading...