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Infinite Series

  1. Apr 15, 2010 #1
    Calculate the summation of i=1 to inf of the summation of j=i to inf of p^(j+i).
    Yes, it is the summation of a summation. p^(j+i) can be seperated into (p^j)*(p^i).
  2. jcsd
  3. Apr 15, 2010 #2


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    Science Advisor

    Write k=j-i, then you need to sum p2i+k with k=0 to ∞ and i=1 to ∞.
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