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guguma
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Homework Statement
Show that E<0 solutions to the infinite square well potential are not applicable (precisely show that boundary conditions are not satisfied when E<0)
Homework Equations
Time independent Schrodinger equation
V(x) = 0 , 0<x<a
V(x) = inf otherwise
The Attempt at a Solution
The heart of the problem lies in defining [tex]k = \sqrt{2mE}/\hbar[/tex] or [tex]K = \sqrt{-2mE}/\hbar[/tex]
if I use k such that E>0 then I can find the boundary conditions and I can find the energy eigenvalues which are also real and positive. When E<0 I can do the exact same thing, I can satisfy the boundary conditions and find the energy eigenvalues which are positive, now this causes a contradiction (E<0 but E>0 in our solution) so that we can say there are no solutions for E<0. But I cannot see how E<0 affects my boundary conditions.
If I use K, then we get the real exponential solutions to the Schrodinger equation and it does not matter whether E<0 or E>0 we cannot satisfy the boundary conditions. Where we should be able to for E>0.
I think I am missing something mathwise here, do I have to (and I mean "have to" as in "must") define a real variable (k,K) when simplifying the Schrodinger Equation I do not think there would be a restriction on that because I may not know how the potential looks like for some stuff. I thought maybe I was being sloppy on complex numbers when I was squaring them but powers of imaginary numbers are defined just as the real numbers.
You see I am confused, why the way I define a variable makes the problem unsolveable (in the case of K).
Thanks in advance
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