Infinitely differentiable

  • Thread starter Ratzinger
  • Start date
  • #1
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Main Question or Discussion Point

infinitely differentiable doesn't care if all the higher derivatives are zeroes (like for polynomials), it only has to be defined...correct?
 

Answers and Replies

  • #2
AKG
Science Advisor
Homework Helper
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3
Correct......
 
  • #3
Hurkyl
Staff Emeritus
Science Advisor
Gold Member
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It's okay for them to all be zero as well!

such as for

[tex]
f(x) = \left\{
\begin{array}{ll}
0 & x = 0 \\
e^{-1/x^2} \quad & x \neq 0
\end{array}
[/tex]

at x = 0.
 

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