- #1
Werg22
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Is this true?
f(x)=sin(x)=x(x-2pi)(x-4pi)(x-6pi)...
edit:
f(x)=sin(x)=x(x-pi)(x-2pi)(x-3pi)(x-4pi)...
f(x)=sin(x)=x(x-2pi)(x-4pi)(x-6pi)...
edit:
f(x)=sin(x)=x(x-pi)(x-2pi)(x-3pi)(x-4pi)...
Last edited:
I was trying to point out that sin(pi) = 0 but your serie would never go to 0.Werg22 said:I'm affraid I do not see what you mean... the serie is infinite...
Werg22 said:Sorry what I really meant is f(x)=sin(x)=x(x-pi)(x-2pi)(x-3pi)(x-4pi)...
Really sorry.