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A toy balloon is inflated with helium at a constant pressure that is 4.2e5 Pa in excess of atmospheric pressure. If the balloon inflates from a volume of 1.4e-4m3 to 9.6e-4m3, how much work is done by the balloon on the surrounding air? answer in J

this is my work

P= 4.2e5Pa + 101300Pa

= 521 300 Pa

dV = (Vf-Vi) = (9.6e-4 - 1.4e-4)

= 0.00082m3

W= 521 300Pa x (0.00082m3)

427.466 J (incorrect on homework server)

I'm guessing it has something to do with the work on the surrounding air...I have been looking in my books and course notes for this and I can't find anything...can anybody help me out??

Any help is appreciated,

Sergio