- #1
Lacero
- 31
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Hi all,
Determine the equilibrium temperature distribution (if it exists). For what values of B, are there solutions.
a) Ut = Uxx + 1, U(x,0) = f(x), Ux(0,t) = 1, U(L,t) = B
b) Ut = Uxx + X - B, U(x,0) = f(x), Ux(0,t) = 0, U(L,t) = 0
a) Assume solution U(x,t) = V(x,t) + K
=> Ut = Vt
=> Uxx = Vxx -- Sub into Ut = Uxx + 1
Vt = Vxx + 1
Now to get homogeneous boundary conditions,
U(0,t) = V(0,t) + K = 1 ?
but K = 1 => V(0,t) = 1?
// Trouble at the BC
b)
Assume solution U(x,t) = V(x,t) + W(x)
=> Ut = Vt
=> Uxx = Vxx + W'' -- Sub into Ut = Uxx + Q(x)
Vt = Vxx + W'' + Q
Now, let W'' + Q = 0 or W'' = -Q
=> Vt = Vxx
V(0,t) = 0
V(L,t) = 0
U(x,0) = V(x,0) + W(x) = f(x)
=> V(x,0) = f(x) - W(x)
Now Solve transient solution, v(x,t)
. .
. .
. .
V(x,t) = (2/L)sum(n=1 to inf)(int((f(x)-W(x))sin(npi/L)xdx)... etc
Now Solve steady state solution, W" = -Q B - X
W" + X + B = 0
. .
. .
W(x) = Scos(zx) + Tsin(zx) + Yp... etc
Now U(x,t) = W(x) + V(x,t)
Am I right at all?
Homework Statement
Determine the equilibrium temperature distribution (if it exists). For what values of B, are there solutions.
Homework Equations
a) Ut = Uxx + 1, U(x,0) = f(x), Ux(0,t) = 1, U(L,t) = B
b) Ut = Uxx + X - B, U(x,0) = f(x), Ux(0,t) = 0, U(L,t) = 0
The Attempt at a Solution
a) Assume solution U(x,t) = V(x,t) + K
=> Ut = Vt
=> Uxx = Vxx -- Sub into Ut = Uxx + 1
Vt = Vxx + 1
Now to get homogeneous boundary conditions,
U(0,t) = V(0,t) + K = 1 ?
but K = 1 => V(0,t) = 1?
// Trouble at the BC
b)
Assume solution U(x,t) = V(x,t) + W(x)
=> Ut = Vt
=> Uxx = Vxx + W'' -- Sub into Ut = Uxx + Q(x)
Vt = Vxx + W'' + Q
Now, let W'' + Q = 0 or W'' = -Q
=> Vt = Vxx
V(0,t) = 0
V(L,t) = 0
U(x,0) = V(x,0) + W(x) = f(x)
=> V(x,0) = f(x) - W(x)
Now Solve transient solution, v(x,t)
. .
. .
. .
V(x,t) = (2/L)sum(n=1 to inf)(int((f(x)-W(x))sin(npi/L)xdx)... etc
Now Solve steady state solution, W" = -Q B - X
W" + X + B = 0
. .
. .
W(x) = Scos(zx) + Tsin(zx) + Yp... etc
Now U(x,t) = W(x) + V(x,t)
Am I right at all?