iac0b said:A ball is launched directly upward from ground level with an initial speed of 18 m/s. (Air resistance is negligible.)
What equation would I use to find the time the ball was in the air?
The formula for finding the time in air for a ball launched upward is t = (2v/g), where t is the time in seconds, v is the initial velocity in meters per second, and g is the acceleration due to gravity (9.8 m/s^2).
To calculate the time in air for a ball launched upward with an initial velocity of 18 m/s, you can plug the values into the formula t = (2v/g). This will give you the time in seconds that the ball is in the air before it reaches its maximum height and starts to fall back down.
No, the formula t = (2v/g) is specifically for a ball launched upward. For a ball launched downward, the formula would be t = (v/g), where t is the time in seconds, v is the initial velocity in meters per second, and g is the acceleration due to gravity.
Air resistance can affect the time in air for a ball launched upward by slowing down the ball's velocity as it travels through the air. This means that it will take longer for the ball to reach its maximum height and fall back down, resulting in a longer time in air.
Other factors that can impact the time in air for a ball launched upward include the angle at which the ball is launched, the mass of the ball, and the elevation of the launch point. These factors can affect the initial velocity and trajectory of the ball, which in turn can affect the time it takes for the ball to reach its maximum height and fall back down.