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## Homework Statement

The moving proton hits the second proton, which we consider to be stationary. In the moment of central strike gap between the protons is 10(-13)m. What was the initial speed of the moving proton? Proton mass is 1.67*10(-27)kg and charge 1.6*10(-19) C.

## Homework Equations

Electric potential energy U=kQq

**/**r

Kinetic energy 1/2 mv2

## The Attempt at a Solution

kinetic energy is transformed into electric potential energy at the point of closest approach:

electric potential energy=kinetic energy of moving proton

From there I find initial speed of moving proton to be v=1.66*10(6) m/s, in book answer is 2.35*10(6) m/s