At the 18th green of the U. S. Open you need to make a 22.0 ft putt to win the tournament. When you hit the ball, giving it an initial speed of 1.27 m/s, it stops 6.00 ft short of the hole. (a) Assuming the deceleration caused by the grass is constant, what should the initial speed have been to just make the putt? m/s (b) What initial speed do you need to just make the remaining 6.00 ft putt? m/s So far, to try and find the inital speed needed to make the putt, I have done the following. 1. 22 feet away from the hole, the putt is 6 feet short, so I subract 6 from 22, and I get 16 feet. 2. Now that I have 16 feet, I take the initial speed of 1.27 m/s and convert it to feet per second. I get 4.166666673 feet per second. 3. Now that both the feet away from the hole (16 feet) and the initial speed (4.166666673 ft/s) are in the same units, I divide them, to get the time it took for the golf ball to travel that distance. I get 3.839999994 or 3.84. 4. Now I am stumped, with these things I have figured out about the problem, how can I use this to find the inital speed I would need to just make the putt? Time it takes golf ball to travel 16 feet away from the hole (3.84 seconds) Total Distance = 22 Feet Golf Ball = 6 feet short from hole as for question (b) I am completly stumped. Any help would be greatly appreciated! Thank you!