Solve the Given initial value problem
[tex] y' = tan ( x ), y ( pi / 4 ) = 3 [/tex]
The Attempt at a Solution
Well I got the answer
[tex] y = sec^2 ( x ) + 5 / 2 [/tex]
The books answer is
[tex] y = 3 - ln (sqrt(2) cos(x) ) [/tex]
Where did I got wrong? Or is the book screwed up?