1. The problem statement, all variables and given/known data Solve the initial value problem [tex]y'=y^2 , y(0)=1[/tex] and determine the interval in which the solution exists. 3. The attempt at a solution So after solving the differential equation, we get [tex] y= 1/(1-t) [/tex] However, I don't understand why the interval is only [tex] (- \infty , 1 ) [/tex] and not [tex](- \infty, 1 ) U ( 1 , \infty)[/tex]. From the y(x) equation, we see that it is only not defined when t=1, so why don't we include the other interval as a solution? Could someone please enlighten me please.