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Initial value problem

  1. Dec 19, 2004 #1


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    Rewrite the differential equation [tex]\frac{dy}{dx}=x{\sqrt{y}}[/tex] in the form y=f(x) given the initial condition f(3)=25.

    I am new to integration so I am unsure about my work on this problem.





    [tex]2y^{\frac{1}{2}}=\frac{1}{2}x^2+ C[/tex]





    If I did it correctly, is there an easier way to do it? If I messed up, where?

  2. jcsd
  3. Dec 19, 2004 #2
    Looks right to me.

    It doesn't seem like that much work to me.
  4. Dec 19, 2004 #3


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    No, it's not a lot of work, I just thought that there might be others ways to arrive at the same answer.

  5. Dec 19, 2004 #4


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    Nope,there's no simpler way to integrate that diff.eq. than the variable separation method.
    Nice work!!

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