Initial Velocity Question

  • Thread starter bwilhelm
  • Start date
  • #1
9
0
Am I anywhere near correct?


Homework Statement


A ball is thrown and upward and reaches it's maximum height in 1.80 sec.

A. Find Initial Velocity
B. Find Max Height Reaced
C. Find Velocity 1.15 sec after being thrown.


Homework Equations





The Attempt at a Solution


A. .5(-9.8)*1.8^2= -15.87 m/sec
B. -15.87+.5(-9.8)*1.8^2 = 31.74m
C. .5(-9.8)1.15^2= -6.48 m/sec
 

Answers and Replies

  • #2
learningphysics
Homework Helper
4,099
6
No, not near correct. For part a, you used a displacement formula... so the result won't be a velocity...

Hint: for part a) use the fact that v2 = v1 + at. You know v2, a and t... use those to calculate v1.

For part b) you made a mistake with the formula... it should be s = v1*t + 1/2 at^2... you didn't multiply v1 by t... and also the v1 is wrong since part a was wrong...

For part c)... here again you use a displacement formula... so the result that comes out will be displacement not a velocity... 1/2 at^2 is a distance not a velocity.
 

Related Threads on Initial Velocity Question

  • Last Post
Replies
7
Views
2K
  • Last Post
3
Replies
62
Views
5K
  • Last Post
Replies
3
Views
2K
  • Last Post
Replies
11
Views
2K
  • Last Post
Replies
6
Views
1K
  • Last Post
Replies
1
Views
2K
  • Last Post
Replies
4
Views
883
  • Last Post
Replies
1
Views
872
  • Last Post
Replies
8
Views
1K
  • Last Post
Replies
2
Views
844
Top