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Homework Help: Initial Velocity question

  1. Sep 9, 2007 #1
    A ball of unknown mass is thrown straight up.

    *maximum height reached in 5.78 seconds
    *acceleration due to gravity 9.8 m/s2

    Calculate initial velocity in m/s

    Would the initial velocity be 9.8 m/s2 x 5.78 s: 56.644 m/s?

    Thats all the information given.
     
  2. jcsd
  3. Sep 9, 2007 #2
    that's what i got

    [tex]v_y=v_{0y}+gt[/tex]

    [tex]-v_{0y}=gt[/tex]
     
  4. Sep 9, 2007 #3
    Not to be redundant with the other post but i got the same=P

    V initial x (Acceleration)(time) = V final

    At the highest point, the velocity is 0 so

    V initial + (-9.8m/s^2)(5.78s) = 0

    V initial = 56.644 m/s
     
  5. Sep 9, 2007 #4
    no prob :) so that's 3 for 56.644 m/s!
     
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