Initial Velocity question

  • Thread starter chemguy990
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  • #1
A ball of unknown mass is thrown straight up.

*maximum height reached in 5.78 seconds
*acceleration due to gravity 9.8 m/s2

Calculate initial velocity in m/s

Would the initial velocity be 9.8 m/s2 x 5.78 s: 56.644 m/s?

Thats all the information given.
 

Answers and Replies

  • #2
1,753
1
A ball of unknown mass is thrown straight up.

*maximum height reached in 5.78 seconds
*acceleration due to gravity 9.8 m/s2

Calculate initial velocity in m/s

Would the initial velocity be 9.8 m/s2 x 5.78 s: 56.644 m/s?

Thats all the information given.
that's what i got

[tex]v_y=v_{0y}+gt[/tex]

[tex]-v_{0y}=gt[/tex]
 
  • #3
4
0
Not to be redundant with the other post but i got the same=P

V initial x (Acceleration)(time) = V final

At the highest point, the velocity is 0 so

V initial + (-9.8m/s^2)(5.78s) = 0

V initial = 56.644 m/s
 
  • #4
1,753
1
Not to be redundant with the other post but i got the same=P

V initial x (Acceleration)(time) = V final

At the highest point, the velocity is 0 so

V initial + (-9.8m/s^2)(5.78s) = 0

V initial = 56.644 m/s
no prob :) so that's 3 for 56.644 m/s!
 

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