# Initial velocity

manimaran1605
A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how? What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).

Staff Emeritus
A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how? What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).

So you're saying that there's NO difference between just releasing the stone from a stationary balloon that isn't moving? Think again.

Zz.

1 person
dauto
A stone released from balloon moving upwards with some constant velocity, the initial velocity of stone is same as the velocity of balloon with opposite sign, but how?
No, not opposite sign. Same sign.
What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).
You're free to think whatever you want. That doesn't make it right.

Mentor
What i thought is that the instant stone is released which goes upwards with balloon, stone which is going upwards would stop (t=0) velocity (u=0).

Think about that for a moment. When you throw a stone upwards, you release it from your hand while your hand is moving upwards rapidly... What happens?