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[tex]

x-\frac{x^3}{6}+\frac{x^5}{120}>\sin x\\

[/tex]

[tex]

R_5=\frac{f^{5}(c)x^5}{5!}

[/tex]

i need to prove that the remainder is negative .

[tex]

\sin x=x-\frac{x^3}{6}+\frac{x^5}{120}+R_5

[/tex]

[tex]

R_5=\frac{cos(c)x^5}{5!}

[/tex]

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# Homework Help: Innequality prove question

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