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Inner Product Spaces

  1. Sep 2, 2012 #1
    What is the most motivating way to introduce general inner product spaces? I am looking for examples which have a real impact. For Euclidean spaces we relate the dot product to the angle between the vectors which most people find tangible. How can we extend this idea to the inner product of general vectors spaces such as the set of matrices, polynomials, functions?
     
  2. jcsd
  3. Sep 2, 2012 #2

    HallsofIvy

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    Actually, you have given the main motivation for inner product spaces: they generalize the Euclidean spaces with dot product. Of course, any finite dimensional space is isomorphic to the Euclidean space of the same dimension so we could just use the "dot product" defined on the Euclidean space. The reason for the more general definitions is to be able to work with infinite dimensional, and in particular, function spaces.

    But inner products are also important in adding a topology to vector spaces so that we can talk about "limits" and "continuity". The most general way we can introduce a topology is to add a "distance" or metric function, a function that maps pairs of vectors to a positive real number such that:
    i) [itex]d(u, v)\ge 0[/itex] and d(u, v)= 0 if and only if u= v.
    ii) [itex]d(u,v)\le d(u, w)+ d(w, v)[/itex] for any vectors, u, v, w.

    We interpret d(u, v) as the distance between vectors u and v (a "metric vector space" in which Cauchy sequences converge is called a "Frechet" space). That doesn't really make use of the algebraic properties of a vector space but leads to a "normed space" which has a norm, a function that maps a single vector to a real number such that
    i) [itex]|v|\ge 0[/itex] and |v|= 0 if and only if v= 0.
    ii) [itex]|u+ v|\le |u|+ |v|[/itex].
    iii) [itex]|\alpha v|= |\alpha| |v|[/itex] for any vector v and scalar [itex]\alpha[/itex] ([itex]|\alpha|[/itex] is the usual absolute value of [itex]\alpha[/itex]).
    and we interpret |v| as the "length" of vector v. Of course, if we have a "length" we have a "distance" and can define d(u, v)= |u- v| so we have all the properties of a "metric vector space" plus additional ones. A normed space in which all Cauchy sequences of vectors converge is called a "Banach space". Other than the Euclidean spaces themselves, the most important example of a Banach space is L1, the set of all function, f, whose absolute values are Lebesque integrable on a given set, U: [itex]\int_U |f(x)|dx[/itex] is finite and we deifine [itex]|f|= \int_U |f(x)|dx[/itex].

    We define an "inner product" on a vector space as a function that maps pairs of vectors to scalars (typically real or complex numbers), satisfying
    i) [itex]<i, i>\ge 0[/itex] and <i, i>= 0 if and only if v= 0
    ii) [itex]<\alpha u, v>= \alpha<u, v>[/itex] for any two vectors, u and v, and any scalar [itex]\alpha[/itex].
    iii)[itex]<u+v, w>= <u, w>+ <v, w>[/itex]
    Once we have an inner product we can define [itex]|v|= \sqrt{<v, v>}[/itex] and have all of the properties of a normed space (which includes all of the properties of a metric vector space) plus additional properties. An inner product space in whichy all Cauchy sequences of vectors converge is called a "Hilbert space". Other than the Euclidean space themselves, the most important Hilbert space is L2, the set of all "square integrable" on set U: [itex]\int_U f^2(x)dx[/itex] is finite. One can show that, if both f and g are square integrable on U, then [itex]\int_U f\bar g dx[/itex] is finite and we can define [itex]<f, g>= \int_U f\bar g dx[/itex].
     
  4. Sep 2, 2012 #3
    Thanls for the detailed reply.
     
  5. Sep 2, 2012 #4

    chiro

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    A simple way to think about the motivation of inner product spaces is that it gives a vector space geometry.

    With inner product spaces you can do projections which has not only a geometric importance, but an importance in terms of an abstract decomposition.
     
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