Inner products and Circles

  1. [​IMG]
    Mostly I'd like to look at the third part of the problem. I'm not sure if this is the correct way to derive the equation:

    So, finding the length of a given vector given this inner product:
    [itex]<(x,y),(x,y)> = 5x^2 + y^2[/itex].

    Taking the length, we have

    [itex]|(x,y)| = \sqrt{5x^2 + y^2}[/itex], which we define as equaling 1. Squaring both sides we find,

    [itex]5x^2 + y^2 = 1[/itex]. I think this is the equation of the circle, but I'm not sure. If it is, then my picture has y-intercepts at 1,-1 and x-intercepts at -sqrt(1/5),sqrt(1/5).

    Is this correct?
     
  2. jcsd
  3. Bacle2

    Bacle2 1,179
    Science Advisor

    I think you're missing some terms from the length:

    <(x,y),(x,y)>=5x2+2(xy+yx)+y2
     
  4. Whoops. You're right. My real equation is [itex]5x^2 -2(xy+xy) +y^2 =1[/itex]. This changes shape of the circle (it's more elongated in quadrants I and III now), but the intercepts remain the same I think. No?
     
  5. Bacle2

    Bacle2 1,179
    Science Advisor

    I think if you do a rotation of the plain, you may be able to get rid of the mixed xy-terms.
     
Know someone interested in this topic? Share a link to this question via email, Google+, Twitter, or Facebook

Have something to add?
Similar discussions for: Inner products and Circles
Loading...