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mathguyz
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Does anyone here know what the indefinite integal of 1/e^x is?
Im an new member and, this is my first post.
Im an new member and, this is my first post.
mathguyz said:Does anyone here know what the indefinite integal of 1/e^x is?
Im an new member and, this is my first post.
sutupidmath said:here it is how you might want to think about it: i am assuming you know how to integrate this, since it is only a tabelar integral
[tex]\int e^{x}dx[/tex], for the other one[tex]\int e^{-x}dx[/tex], take the substitution -x=t, so now we have dx=-dt, now substitute back on the integral we get:
[tex]\int e^{t}(-dt)=-\int e^{t}dt=-e^t+c [/tex] substituting back for the original variable we get [tex] -e^{-x}+c[/tex]
JasonRox said:Why not just let u = e^-x?
No need for substitution here.
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