A child on a Ferris wheel is moving vertically upward at 6.20 m/s at one instant, and 0.150 s later is moving at 6.20 m/s at an angle of 41.5° above the horizontal. Estimate the child's instantaneous acceleration. What is the magnitude? What is the direction? (degrees below the horizon) I tried using the equation ax=V(cos)THETA - Vinitial/TIME ay=V(sin)THETA-0/TIME Then taking the squareroot of the two answers above squared, but this did not work. where am i going wrong?