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tjsuglia
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A child on a Ferris wheel is moving vertically upward at 6.20 m/s at one instant, and 0.150 s later is moving at 6.20 m/s at an angle of 41.5° above the horizontal. Estimate the child's instantaneous acceleration.
What is the magnitude?
What is the direction? (degrees below the horizon)
I tried using the equation
ax=V(cos)THETA - Vinitial/TIME
ay=V(sin)THETA-0/TIME
Then taking the squareroot of the two answers above squared, but this did not work. where am i going wrong?
What is the magnitude?
What is the direction? (degrees below the horizon)
I tried using the equation
ax=V(cos)THETA - Vinitial/TIME
ay=V(sin)THETA-0/TIME
Then taking the squareroot of the two answers above squared, but this did not work. where am i going wrong?