1. The problem statement, all variables and given/known data In the inductive circuit shown in Figure 2, the switch S1 is closed 0.75s after switch S2 is closed. Calculate the instantaneous current in the coil 1.5s after switch S1 is closed. 2. Relevant equations T=L/R I=V/R 3. The attempt at a solution When S2 is closed: T=L/R =2.4/7.2 =0.333 =333ms IMAX=V/R =24/7.2 =3.33A At time 0.75s S1 is closed, the current is: i1=IMAX(1-e^-t/T) =24/3.6(1-e^-750/333) =5.97A When S1 is closed current flows through the 3.6ohm resistor and decays: Time constant is: T=L/R =2.4/3.6 =0.666 =666ms Current after 1.5s after S1 is closed: i2=i1e^-t/T =5.97e^-(1.5x10^-3/666) =5.97A This cannot be correct?