Solving Hexadecimal Unsigned 8-bit Integer Multiplication

[illidari]

Homework Statement

a) 50 b) 23

Product of the hexadecimal unsigned 8-bit integers

Homework Equations

Step Action |||||||||| Multiplicand ||||||| Product/Multiplier
0 Initial Vals ||||||||| 101 000 ||||||| 000 000 010 011

The Attempt at a Solution

How did they get the initial values? 50 should be the multiplicand
50 = 5*16 + 0*1 = 80
80 = 1010000 in binary which is not 101 000

23 hex = 35 decimal = 100011 binary ... does not equal 10011I somehow have an extra zero in both :(?

 

[gneill]

Perhaps they meant octal rather than hex?

 

[illidari]

a. 50 × 23
Step Action--- Multiplier ----Multiplicand---- Product
0 Initial Val ---010 011----- 000 000 101 000 ----000 000 000 000

that was the previous question, unsigned octal 6 bit integers

Guessing they used octal in the solution manual screwing me up :(?

 

[gneill]

Guessing they used octal in the solution manual screwing me up :(?

It's been known to happen

 

[DeeNos]

Based on the given information, it seems that the initial values were incorrectly entered. The correct values for 50 and 23 in hexadecimal are 32 and 17, respectively. Therefore, the correct initial values should be 00100000 for 32 and 00010001 for 17. It is important to double check all values and conversions when solving mathematical problems to avoid errors.