Find the area of the region y = x x + 2y = 0 2x + y = 3 So, I decided to integrate with respect to y. And got the integral from -1 to 0 of [(3-y)/2 - (-2y)]dy + the integral from 0 to 1 of [(3-y)/2 - y]dy. Integrating that, I got [3y/2 + 3y^2/4]0-1 + [3y/2 - 3y^2/4]10 = 0 However, the answer is 3/2. The book integrated with respect to x, but I wanted to do it in terms of y. Is it possible integrating it with respect to y?