[tex]\int 96cos^4(6x) * dx[/tex](adsbygoogle = window.adsbygoogle || []).push({});

ok first i take out the 96 cause it's constant!

[tex] 96 \int cos^4(6x) * dx[/tex]

[tex] 96 \int (cos^2(6x)^2) * dx [/tex]

ok now with that setup, i can know use the half-angel formula!

[tex] 96 \int (\frac{1+cos(12x)}{2})^2 [/tex]

squared the problem...

[tex] 24 \int (1+ 2cos(12x) + (cos12x)^2 [/tex]

now to use the half-angle idents agian..

[tex] 24 \int 1 +2cos(12x) + 1/2(1+cos24x) [/tex]

can someone tell me if im doing this correctly before i integral the problem?

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# Homework Help: Integral! Cal. 2!

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