- #1

planauts

- 86

- 0

## Homework Statement

Find the values of a > 0, such that [tex] \int_{a }^{a^2} \frac{1}{1+x^2} dx = 0.22[/tex]

## The Attempt at a Solution

I integrated it and got:

[tex]\int_{a }^{a^2} \frac{1}{1+x^2} dx = 0.22 [/tex]

[tex]arctan(a^2) - arctan(a) = 0.22[/tex]

I am stuck after this, how would I solve this :-/

Thanks