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## Homework Statement

Find the value of a such that:

[tex]\int_{0 }^{a } cos^2 (x) dx[/tex]

## The Attempt at a Solution

[tex]\int_{0}^{a}\frac{1}{2} (1+cos (2x))[/tex]

[tex]\frac{x}{2} + \frac{(sin(2x)}{4} [/tex]

[tex]\frac{a}{2} + \frac{sin(2a)}{4} - 0 - 0 = 0.740[/tex]

[tex]\frac{a}{2} + \frac{sin(2a)}{4} = 0.740[/tex]

[tex] 2a + sin(2a) = 2.96[/tex]

I am stuck after this...How would I solve the trig equation?

Maybe...[tex] m + sin(m) = 2.96[/tex]

where m = 2a

But I don't think that will get me anywhere :-/

Thanks for your help!