# Integral + Complex Conjugate

1. Apr 11, 2012

### Scootertaj

1. The problem statement, all variables and given/known data
Show that the following = 0:
$\int_{-\infty}^{+\infty} \! i*(\overline{d/dx(sin(x)du/dx})*u \, \mathrm{d} x + \int_{-\infty}^{+\infty} \! \overline{u}*(d/dx(sin(x)du/dx) \, \mathrm{d} x$ where $\overline{u}$ = complex conjugate of u and * is the dot product.

2. Work so far
My thoughts: $\int_{-\infty}^{+\infty} \! i*(\overline{d/dx(sin(x)du/dx})*u \, \mathrm{d} x + \int_{-\infty}^{+\infty} \! \overline{u}*(d/dx(sin(x)du/dx) \, \mathrm{d} x$
=
$\int_{-\infty}^{+\infty} \! -i*(d/dx(sin(x)du/dx)*u \, \mathrm{d} x + \int_{-\infty}^{+\infty} \! \overline{u}*(d/dx(sin(x)du/dx) \, \mathrm{d} x$

But I don't even know if that's right.

2. Apr 15, 2012

Bump.