g(x) = integral 0 to lnx (sin(t)+t^3/2))dt(adsbygoogle = window.adsbygoogle || []).push({});

find d/dx g(x):

let u = lnx

= sin(u) + u^3/2 du/dx

= sin(lnx)(1/x) + x^3/2(1/x)

Thanks

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# Homework Help: Integral Derivative

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