Integral Divisors

  • Thread starter Gear300
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  • #1
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Edit: I'm shifting to a more general question:
If the prime factorization of an integer n is given by

n = p1v1p2v2⋅⋅⋅pkvk

then what would be a proof for the number of positive divisors of n being

d(n) = (v1 + 1)(v2 + 1)⋅⋅⋅(vk + 1)
 
Last edited:

Answers and Replies

  • #2
tiny-tim
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I am supposed to find the number of positive integral divisors of 2r3s. The number is (r+1)(s+1). I tried a number of ways, but I'm not getting the intended answer. Any help?

Hi Gear300! :wink:

Just write out the typical divisor …

what does it look like? :smile:
 
  • #3
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In each divisor pik appear with 0 <= k <= vi
 

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