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Integral Divisors

  1. Apr 26, 2009 #1
    Edit: I'm shifting to a more general question:
    If the prime factorization of an integer n is given by

    n = p1v1p2v2⋅⋅⋅pkvk

    then what would be a proof for the number of positive divisors of n being

    d(n) = (v1 + 1)(v2 + 1)⋅⋅⋅(vk + 1)
     
    Last edited: Apr 26, 2009
  2. jcsd
  3. Apr 26, 2009 #2

    tiny-tim

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    Hi Gear300! :wink:

    Just write out the typical divisor …

    what does it look like? :smile:
     
  4. Apr 26, 2009 #3
    In each divisor pik appear with 0 <= k <= vi
     
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