- #1
rebeka
- 44
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integral dx/sqrt(x - a)
integral dx/sqrt(1/ax)
integral dx/sqrt(1/ax)
Last edited:
HallsofIvy said:[tex]\int \sqrt{x-a}dx[/tex]
The formula for "Integral dx/sqrt(x - a)integral dx/sqrt(1/ax)" is ∫ dx/√(x-a) * ∫ dx/√(1/ax).
The purpose of the "Integral dx/sqrt(x - a)integral dx/sqrt(1/ax)" formula is to solve for the integral of two functions that contain square roots.
The "Integral dx/sqrt(x - a)integral dx/sqrt(1/ax)" formula has limitations in that it can only be used for integrals involving square roots and cannot be used for other types of integrals.
The "Integral dx/sqrt(x - a)integral dx/sqrt(1/ax)" formula is commonly used in physics and engineering to solve for the area under a curve that contains square roots.
Yes, there are alternative methods for solving integrals involving square roots such as substitution, integration by parts, and trigonometric substitutions.