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Can someone help me with this integral?
e^(-1/x)
e^(-1/x)
If the problem were [itex]\int e^u du[/itex], but it isn't and there is no good way to change it to that form.Just follow the rules for exponential integration.
[tex]\int[/tex] [tex]e^{u}[/tex] du = [tex]e^{u}[/tex] + C
Thanks
Matt