I've been trying to solve differential equation:(adsbygoogle = window.adsbygoogle || []).push({});

[tex] y' = \frac{x+y}{x-y} [/tex]

I came to the point where I got following integrals:

[tex]\int \frac{(1-z) \cdot \,dz}{1+z^2} = \int \frac{dx}{x} [/tex]

The integral on the left side is the problem. I tried substitution:

[tex]t = 1+z^2 [/tex]

but I always end up with one dz left in the numerator.

I did the differential equation with numerator and denumerator inversed without problems, but I'm stuck on this one and I have a feeling that I can't figure out a trivial thing.

Any hints?

Thanks for help!

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# Integral giving me headache

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