heres a funky one I can't do(adsbygoogle = window.adsbygoogle || []).push({});

[tex]

\int \frac{6t \,dt}{\sqrt{1-2t^2}}

[/tex]

here's what I've done

I changed it so it looks like this:

[tex]

\int 6t(1-2t^2)^{-1/2} dt

[/tex]

Then I substituted u for 1-2t^2 and got du= -4t*dt

Where do I go from here?

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# Homework Help: Integral help

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