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Integral help

  1. Oct 9, 2007 #1
    1. The problem statement, all variables and given/known data

    [tex]\int x/2x-20)^(1/2) [/tex]

    3. The attempt at a solution

    I did u sub got the [tex]\int (u+20)/(2u^1/2)du [/tex] which became (1/6)(2x-20)^(3/2) + 10(2x-20)^(1/2)

    Is this right? What am i doing wrong if it is not.
  2. jcsd
  3. Oct 9, 2007 #2


    User Avatar
    Science Advisor

    Do you mean
    If so that is the same as
    [tex]\int [(1/2)u^{1/2}+ 10u^{-1/2}]du[/tex]
    I don't see how you would get 2x-20- since there is no x in the original integral!
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