- #1
madahmad1
- 42
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If you are told to evaluate the integral and are given this problem:
∫ (e√x / √x) dx
This reads that the integral of (e) to the power of square root of x divided by the square root of x multiplied by the derivative of x is……
I have tried solving it and came up with this, is this correct if not please show me what I did wrong and how I can solve it.
y = x2 + 2
y = sin x
0 ≤ x ≤ π
π π π π
A(D) = ∫0 (x2 + 2 – sin x) dx = ∫0 x2dx + 2 ∫0 dx - ∫0 sin x dx =
π π π
[x 3 / 3 ]0 + 2[x]0 + [cos x]0 = π/3 + 2π – 2
π
[cos x]0 = cos π – cos 0 = -1 – 1 = -2
Is this correct?
the integral goes from zero to pi. and x2 is x squared. Any help is appreciated.
∫ (e√x / √x) dx
This reads that the integral of (e) to the power of square root of x divided by the square root of x multiplied by the derivative of x is……
I have tried solving it and came up with this, is this correct if not please show me what I did wrong and how I can solve it.
y = x2 + 2
y = sin x
0 ≤ x ≤ π
π π π π
A(D) = ∫0 (x2 + 2 – sin x) dx = ∫0 x2dx + 2 ∫0 dx - ∫0 sin x dx =
π π π
[x 3 / 3 ]0 + 2[x]0 + [cos x]0 = π/3 + 2π – 2
π
[cos x]0 = cos π – cos 0 = -1 – 1 = -2
Is this correct?
the integral goes from zero to pi. and x2 is x squared. Any help is appreciated.